Question

磷酸二氢钾和磷酸氢二钾混合后PH如何计算?

Answer 1

1.K2=0.12*[H+]/0.08=1.51*10^-7

[H+]=1.01*10^-7 pH=7.0

2.K1=0.08*[H+]/[H3PO4]=7.08*10^-3

[H3PO4]=1.14*10^-6

3.K3=[PO4(3-)]*[H+]/0.12=4.17X10^-13

[PO4(3-)]=4.97*10^-7