Question

有关数列的一道题在数列an中 a1=-3 an=2an-1+2^n+3 n大于等于2 且为正整数1）求a2 a3 的值2

Answer 1

a2 = -6+4+3=1

a3 = 2+8+3 = 13

an=2an-1+2^n+3 , an - a(n-1) = a(n-1) + 2^n + 3

2^n*bn - 2^(n-1)*b(n-1) = 2^(n-1)*b^(n-1) + 2^n,

两边除以2^（n-1）：

2bn - b(n-1) = b(n-1) + 2 , bn = b(n-1) ...