log2(5/4)
log2 (2^x-1)·log2 [2^(x+1)-2]
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相关问题
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log2x^2=log2(根号2-1)-log2(根号2+1),求x+1/x
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log2(2x-1)2+log2x=1
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为什么 log2[√(x^2+1)-x]=log2{1/[√(x^2+1)+x]}
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不等式log2(2^x-1)·log2(2^(x+1)-2
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已知log2(x^2)=log2(根号2-1)-log2(根号2+1),求x+1/x
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log2（2x-1）＞log1/2（1-3x）
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设函数f(x)＝log2x+1x−1+log2(x−1)+log2(p−x)，
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log2(x-1)>2定义域log2(x-1)>2 定义域
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解2log2^(x-5)=log2^(x-1)+1
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f(x)=log^2(x+1)/(x-1)+log^2(x-1)+log^2(p-x)的值域（负无穷,log^(p+1)