Question

已知a=999x+1000,b=999x+1001,c=999x+1002 求多项式a^+b^+c^-ab-ac-cb的

Answer 1

a=999x+1000,b=999x+1001,c=999x+1002

∴a-b=-1

b-c=-1

c-a=2

a²+b²+c²-ab-bc-ca

=(a²-2ab+b²+b²-2bc+c²+c²-2ca+a²)/2

=[(a-b)²+(b-c)²+(c-a)²]/2

=[(-1)²+(-1)²+2²]/2

=3