计算: 1+tan45° 2sin30° -3cot60°的值为______.
1个回答
原式=
1+1
1 -3×
3
3 =2-
3 .
相关问题
计算:(1)2sin30°+3tan30°+cot45°;(2)sin45°+tan60°cos30°;(3) 3cot
计算:sin30°+cos60°-cot45°-tan60°•tan30°
计算:(tan45°+cot30°)\(cot45°—tan60°)
sin30°+cot45°+tan60°-cot30°
求值:2sin30°-2cos60°+cot45°•tan45°.
计算:[tan45°-3cot60°/cos30°-sin30°+cos245°
求2sin60°−tan45°3cot60°+2cos60°•cot45°的值.
求 2sin60°-tan45° 3cot60°+2cos60°•cot45° 的值.
3tan30°-cot45°+2sin60°+cos60°=?
计算:(sin60°−cos45°)(cos30°+sin45°)cos245°+cot60°•sin60°-3cot6