因为△ABC≌△ADE
所以∠BAC=∠DAE
即∠BAE+∠EAC=∠DAC+∠CAE
因为∠EAC=∠CAE
所以∠BAE=∠DAC
因为∠BAD=∠BAE+∠CAE+∠DAC
所以100°=∠BAE+40°+∠DAC
=2∠BAE+40°
∠BAE=(100°-40°)/2=30°
∠BAC=∠BAE+∠CAE
=30°+40°=70°
因为△ABC≌△ADE
所以∠BAC=∠DAE
即∠BAE+∠EAC=∠DAC+∠CAE
因为∠EAC=∠CAE
所以∠BAE=∠DAC
因为∠BAD=∠BAE+∠CAE+∠DAC
所以100°=∠BAE+40°+∠DAC
=2∠BAE+40°
∠BAE=(100°-40°)/2=30°
∠BAC=∠BAE+∠CAE
=30°+40°=70°