计算:(2x^2)^3-6x^3(x^3+2x^2+x);(x+y+z)(x+y-z)
1个回答
第一题:原式=8x^6-6x^4(x+1)^2=2x^4[4^2-3(x+1)^2]=2x^4(x^2-6x-3)
第二题:原式=(x+y)^2-z^2=x^2+y^2-z^2+2xy
相关问题
证明:(y+z-2x)3+(z+x-2y)3+(x+y-2z)3=3(y+z-2x)(z+x-2y)(x+y-2z).
2x-y=7 x+y+z=25x+3y+z=2 x-2y+z=-1 3x-4z=4 x+2y+3z=-1x+y-z=6x
计算(x+2y-3z)的平方+(x-2y+3z)(x+2y-3z)
(1)3x+4y=15 2y-z=2 x+2z=9 (2) x+y+z=8 2x+3y-z=6 3x-y+z=8 (3)
x^2(y+z)+y^2(z+x)+z^2(x+y)-(x^3+y^3+z^3)-2xyz
计算:1.(-x+2y+3z)(x-2y-3z) 2.[(x/2+3y)^2-(y/2+x)^2+(3x-2/y)^2-
x+y+z=3(1) x+2y+3z=6(2) 2x+y+2z=5(3)
一.{x+2y+3z=14 2x-y-z=-3 3x+y+z=8 二.{3X-2Y-2Z=3 2X+2Y+3Z=12 X
2X+Y+Z=10,X+2Y+Z=-6,X+Y+2Z=8 5X+4Y-3Y=13,2X-3Y+7Z=19,3X-Y=2X
因式分解X2(Y+Z)+Y2(Z+X)+Z2(X+Y)-(X3+Y3+Z3)-2XYZ