1.2πR=25012
R=12506/π
r=(3/4)*R=18759/(2π)
S=πr^2=π*(18759/(2π))^2=18759^2/(4π)≈28003318.68
2.设正方形边长为a
S=a^2=20
a=√20=2√5
Rmax=a/2=√5
Smax=πRmax^2=5π
3.S三角形=1/2×底×高
S三角形=12.5
1.2πR=25012
R=12506/π
r=(3/4)*R=18759/(2π)
S=πr^2=π*(18759/(2π))^2=18759^2/(4π)≈28003318.68
2.设正方形边长为a
S=a^2=20
a=√20=2√5
Rmax=a/2=√5
Smax=πRmax^2=5π
3.S三角形=1/2×底×高
S三角形=12.5