(x^2+3x+2)(4x^2+8x+3)+90

1个回答

(x²+3x+2)(4x²+8x+3)+90
=(x+1)(x+2)(2x+1)(2x+3)+90
=-(x+1)(x+2)(2x+1)(2x+3)-90
=-｛√［(x+1)(x+2)(2x+1)(2x+3)］｝²-(√90‍‍‍)²‍‍‍‍‍
=-｛｛√［(x+1)(x+2)(2x+1)(2x+3)］｝-(√90‍‍‍)｝｛｛√［(x+1)(x+2)(2x+1)(2x+3)］｝+(√90‍‍‍)｝