f(x)=[(cosx)^2-(sinx)^2]+√3sin2x=cos2x+√3sin2x=2sin(2x+π/6),
最小正周期T=π,
由-π/2+2kπ≤2x+π/6≤π/2+2kπ,k∈Z解得:-π/3+kπ≤x≤π/6+kπ,k∈Z,
故:函数fx的最小正周期是π;
单调递增区间是:[-π/3+kπ,π/6+kπ],k∈Z,
f(x)=[(cosx)^2-(sinx)^2]+√3sin2x=cos2x+√3sin2x=2sin(2x+π/6),
最小正周期T=π,
由-π/2+2kπ≤2x+π/6≤π/2+2kπ,k∈Z解得:-π/3+kπ≤x≤π/6+kπ,k∈Z,
故:函数fx的最小正周期是π;
单调递增区间是:[-π/3+kπ,π/6+kπ],k∈Z,