Question

直线AB CD相交于o,OD平分角AOF,OE垂直CD于O,角EOA=50度,求角COB和角BOF的度数.

Answer 1

∠BOC=180-∠AOE-∠COE=180-50-90=40

∠AOD=∠DOF=90-∠AOE=90-50=40,

∠BOF=180-∠AOF=180-2∠AOD=180-80=100