Question

已知x^2-4x+3=(x-1)^2+m(x-1)+n,求m、n的值

Answer 1

x^2-4x+3=(x-1)^2+m(x-1)+n

x²-4x+3

=x²-2x+1+mx-m+n

=x²-(2-m)x+(1-m+n)

-4=-(2-m),m=-2,

1-m+n=3,1-(-2)+n=3,n=0;