Question

1.如果单项式-3x^2a-by^2与x^3a+by^5a+8b是同类项,那么这两个单项式的积为（）.A.-3x^10y

Answer 1

1) 5a+8b=2,2a-b=3a+b,a+2b=0所以,a=2,b= -1-3x^(2a-b)*y^2= -3x^5*y^2x^(3a+b)*y^(5a+8b)=x^5*y^2两个单项式的积= -3x^10*y^4,选择A2）x^2*y^3=0,所以,y0,原式= -2xy*1/2*x^5*(-y^7)=x^6*y^8当x