已知弧长C=87.8,弦长L=77.3,求半径R?
Rn+1=(1+(L-2*Rn*SIN(C/(2*Rn)))/(L-C*COS(C/(2*Rn))))*Rn
R0=51
R1=50.868
R2=50.868
R=50.868
已知弧长87.8,弦长77.3,求半径?
已知弧长C=87.8,弦长L=77.3,求半径R?
Rn+1=(1+(L-2*Rn*SIN(C/(2*Rn)))/(L-C*COS(C/(2*Rn))))*Rn
R0=51
R1=50.868
R2=50.868
R=50.868