Question

怎么在matlab中画出方程11.29x=0.45[11.29(x+y)]^0.78的曲线,其中0

Answer 1

clear,clc;

x=0:0.02:0.7;

y=(11.29*x/0.45).^(-0.78)/11.29-x

plot(x,y)

（

y =

Columns 1 through 14

Inf 0.1317 0.0483 0.0044 -0.0286 -0.0568 -0.0825 -0.1068 -0.1300 -0.1527 -0.1748 -0.1966 -0.2182 -0.2395

Columns 15 through 28

-0.2606 -0.2817 -0.3026 -0.3234 -0.3441 -0.3647 -0.3853 -0.4059 -0.4264 -0.4469 -0.4673 -0.4877 -0.5081 -0.5284

Columns 29 through 36

-0.5487 -0.5690 -0.5893 -0.6096 -0.6298 -0.6501 -0.6703 -0.6905

）

注：你给的范围0