(3x+5)/(x+2)(x+3)=A/(x+2)+B/(x+3)
(3x+5)/(x+2)(x+3)=[A(x+3)+B(x+2)]/[(x+2)(x+3)]
所以3x+5=A(x+3)+B(x+2)=(A+B)x+(3A+2B)
所以3=A+B,3A+2B=5
2A+2B=6
3A+2B=5
A=-1
B=3-A=4
(3x+5)/(x+2)(x+3)=A/(x+2)+B/(x+3)
(3x+5)/(x+2)(x+3)=[A(x+3)+B(x+2)]/[(x+2)(x+3)]
所以3x+5=A(x+3)+B(x+2)=(A+B)x+(3A+2B)
所以3=A+B,3A+2B=5
2A+2B=6
3A+2B=5
A=-1
B=3-A=4