[(a+1)(a-1)+1(a-1)²]×aa-1
=【(a+1)(a-1)+1】(a-1)²xaa-1
=a²(a-1)²xaa-1
=a3/(a-1)3
a的3次方/（a-1）的3次方
记得给满意啊
有一个初二的解方程怎么算:[(a+1)\(a-1)+1\(a-1)²]×a\a-1
[(a+1)(a-1)+1(a-1)²]×aa-1
=【(a+1)(a-1)+1】(a-1)²xaa-1
=a²(a-1)²xaa-1
=a3/(a-1)3
a的3次方/（a-1）的3次方
记得给满意啊