第17题,已知向量a=(√3,-sinwx/2),向量b=(sinwx,2sinwx/2),函数f(x)=向量a向量b+

1个回答

  • 向量a=(√3,-sinwx/2),向量b=(sinwx,2sinwx/2)

    f(x)=ab+m=√3sinwx-2sin^2wx/2+m

    =√3sinwx-(1-coswx)+m

    =√3sinwx+coswx-1+m

    =2(√3/2sinwx+1/2coswx)+m-1

    =2sin(wx+π/6)+m-1

    w=2π/T=2π/3π=2/3

    f(x)==2sin(2/3*x+π/6)+m-1,

    X在[0,π]上f(x)最小值=0

    -2+m-1=0

    m=3

    即有,w=2/3,m=3

    2)f(x)==2sin(2/3*x+π/6)+2

    (2a-√2c)cosB=√2bcosC

    2sinAcosB-√2sinCcosB=√2sinBcosC

    2sinAcosB-√2(sinCcosB+sinBcosC)=0

    2sinAcosB-√2sin(C+B)=0

    2sinAcosB-√2sinA=0

    cosB=√2/2

    B=π/4

    A+C=3π/4

    A=3π/4-C

    f(A)=2sin(2/3*A+π/6)+2=2sin[2/3*(3π/4-C)+π/6]+2

    =2sin[π/2-2/3*C+π/6]+2

    =2cos(2/3*C-π/6)+2

    C在(0,3π/4)

    2/3*C-π/6在(-π/6,π/3)

    f(A)=2cos(2/3*C-π/6)+2的值域为(3,4)

    3