求sin12*sin24*sin48*sin96=?

1个回答

  • sin12*sin24*sin48*sin96

    =(sin96*sin24)(sin48*sin12)

    = -1/2[cos120-cos72]*(-1/2)[cos60-cos36]

    = 1/4(-1/2-cos72)(1/2-cos36)

    = 1/4(cos72+1/2)(cos36-1/2)

    = 1/4cos72cos36+1/8(cos36-cos72)-1/16

    = 1/4cos72cos36+1/8*(-2)sin54sin(-18)-1/16

    = 1/4cos72cos36+1/4cos36cos72-1/16

    =1/2cos36cos72-1/16

    =1/4*(2sin36cos36cos72)/sin36-1/16

    =1/4*sin72cos72/sin36-1/16

    =1/8*sin144/sin36-1/16

    =1/8-1/16

    =1/16