Question

有一个质量为7.8kg的正方体物块,把它放在1m^2的水平桌面中央,物块产生的压强为7.8*10^3Pa.

Answer 1

N = G = mg =(7.8 kg)(10 N/kg) = 78 N

S = N/P = (78 N)/(7.8 kPa) = 0.01 m^2