Question

已知:3|x+1|+2(y-1)^2=0,求多项式(x^2+4xy-2y^2)-(x^2+y)-2(y^2+xy)-1/

Answer 1

3|x+1|+2(y-1)^2=0

x+1=0

y-1=0

x=-1

y=1

(x^2+4xy-2y^2)-(x^2+y)-2(y^2+xy)-1/2(x-8y^2)

=x^2+4xy-2y^2-x^2-y-2y^2-2xy-1/2x+4y^2

=2xy-1/2x

=2*(-1)*1-1/2*(-1)

=-2+1/2

=-3/2