∫[dx(x^3)/√(1-x^2)]dx=-(1/3)(x^2+2)√(1-x^2)+C1
分部积分,原式=∫arccosxd[-(1/3)(x^2+2)√(1-x^2)]
=-(1/3)(x^2+2)[√(1-x^2)]arccosx-(x/9)(x^2+6)+C
∫[dx(x^3)/√(1-x^2)]dx=-(1/3)(x^2+2)√(1-x^2)+C1
分部积分,原式=∫arccosxd[-(1/3)(x^2+2)√(1-x^2)]
=-(1/3)(x^2+2)[√(1-x^2)]arccosx-(x/9)(x^2+6)+C