Question

（2x的平方-8x+16）/（x的平方-4x+4）=2x/x-2化简

Answer 1

(2x^2-8x+16)/(x^2-4x+4)=2x/(x-2)

2(x^2-4x+8)/(x-2)^2=2x/(x-2)

(x^2-4x+8)/(x-2)=x

x^2-4x+8=x^2-2x

2x-8=0

x=4