x²+2xy+y²分之x与x+y分之y
x²+2xy+y²分之x=x/(x+y)²
x+y分之y=y/(x+y)=(xy+y²)/(x+y)²
x²+4x分之x+4与x【x-5】-2【x-5】分之x-5
x²+4x分之x+4=(x+4)/x(x+4)=1/x=(x-2)/(x²-2x)
x【x-5】-2【x-5】分之x-5=(x-5)/[(x-5)(x-2)]=1/(x-2)=x/(x²-2x)
x²+2xy+y²分之x与x+y分之y
x²+2xy+y²分之x=x/(x+y)²
x+y分之y=y/(x+y)=(xy+y²)/(x+y)²
x²+4x分之x+4与x【x-5】-2【x-5】分之x-5
x²+4x分之x+4=(x+4)/x(x+4)=1/x=(x-2)/(x²-2x)
x【x-5】-2【x-5】分之x-5=(x-5)/[(x-5)(x-2)]=1/(x-2)=x/(x²-2x)