Question

将电阻R1与R2串联后接到电压为3V的电源上,已知电阻R1=3Ω,且消耗的功率P1=0.12W

Answer 1

I^2*R1=P1

I=(P1/R1)^1/2=0.2A

U1=I*R1=0.2*3=0.6V

P2=UI-P1=3*0.2-0.12=0.48W