求不定积分∫x ln^2xdx

1个回答

  • 原式=1/2∫ln²xdx²

    =1/2*x²ln²x-1/2∫x²dln²x

    =1/2*x²ln²x-1/2∫x²*2lnx*1/xdx

    =1/2*x²ln²x-1/2∫lnxdx²

    =1/2*x²ln²x-1/2*x²lnx-1/2∫x²dlnx

    =1/2*x²ln²x-1/2*x²lnx-1/2∫x²*1/xdx

    =1/2*x²ln²x-1/2*x²lnx-1/2∫xdx

    =1/2*x²ln²x-1/2*x²lnx-1/4*x²+C