两根之和是x1+x2=sin(π/5),x1x2=cos(π/5)
tan[arctanx1+arctanx2]=(x1+x2)/(1-x1x2)=sin(π/5)/[1-cos(π/5)]
设X1,X2是方程x2-xsin(π/5)+cos(π/5)=0的两根,则arctanx1+arctanx2的值是?
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