Question

1.设56 a次方=14,用a表示log7 56

Answer 1

1.log56 14=(log56 7)+(log56 2)=a

log7 56=1/(log56 7)=1/[a-(log56 2)]

2.log32 18

=(log32 9)+(log32 2)

=(2log32 3)+0.2

=(0.2*2log2 3)+0.2

=2/(5m)+1/5

对于log56 2 我也无能为力了,应该不用再化简了吧,我用计算器算过了,上面的答案是正确的