Question

已知数a,b,c满足下列条件:|a+1|+(b-2)^2+4(c^2)+4c+1=0,求[(abc)^25]÷[(a^1

Answer 1

4(c^2)+4c+1=（2c+1）^2>=0

(b-2)^2>=0

|a+1|>=0

因为:|a+1|+(b-2)^2+4(c^2)+4c+1=0

所以（2c+1）^2=0 c=-1/2

|a+1|=0 a=-1

(b-2)^2=0 b=2

abc=1

a^11=-1

bc=-1

(b^8)(c^7)=(bc)^7*b=-2

原式=1/2