a(a+1)-a(aa-4)/(a+1)(aa-2a)(a+2)
1个回答
=a(a+1)-a(a-2)(a+2)/a(a-2)(a+2)(a+1)
=a(a+1)-(a+1)
=(a-1)(a+1)
=aa-1
相关问题
(1)计算:(a2−4a2−4a+4+2−aa+2)÷aa−2
求计算元素有规律的行列式2 a a a aa 2 a a aa a 2 a aa a a 2 aa a a a 2还有1
计算:(a-1+4aa-1)(1+a-4aa+1).
设a1,a2为n维列向量,A为n阶正交矩阵,证明:(1)[Aa1,Aa2]=[a1,a2] (2){Aa1}={a1}
设A是三阶矩阵,a1,a2,a3是列向量,且线性无关,Aa1=a1-a2+2a3,Aa2=a1+a2+3a3,Aa3=-
2/a-1+(a+3)/1-aa=
计算:(a+2a2−2a−a−1a2−4a+4)÷4−aa2−2a.
计算:(1)[1/a−1−aa−1];(2)a2a2+2a•(a2a−2−4a−2);(3)a2+1a−1−a+1;(4
设三维列向量a1,a2,a3线性无关,A是三阶矩阵,且有Aa1=a1+2a2+3a3,Aa2=2a2+3a3,Aa3=3
已知a1,a2,a3线性无关,若a1+aa2,2a1+a2+aa3,a1+2a2-a3亦线性无关,求a