f(x)=[(x-1)^2] [(x+b)] [e^x]
f '(x)=2(x-1) (x+b)[e^x] + [(x-1)^2] [(x+b)] [e^x] + [(x-1)^2] [e^x]
f ‘'(x)=2(x+b) [e^x] + 2(x-1) [e^x] + 2(x-1) (x+b) [e^x]
+ 2(x-1) (x+b)[e^x] + [(x-1)^2] [(x+b)] [e^x] + [(x-1)^2] [e^x]
+ 2(x-1) [e^x] + [(x-1)^2] [e^x]
因为x=1是f(x)的一个极大值,所以f ’'(1)