Question

高数题--已知lim(x→∞）[(x3/x2+x-1)-(ax+b)]=0,⑴求a,b的值⑵曲线y=x3/x2+x-1与

Answer 1

lim(x→∞）[(x3/x2+x-1)-(ax+b)]=0,则（lim(x→∞）[(1-a)x3+(a+b)x2+(b-a）x-b]/(x2+x-1)=0.即1-a=0.b=0.a=1.