Question

将0.4各氢氧化钠配成0.1升溶液,该溶液的ph为多少 .恰好中和上述溶液需盐酸多少摩

Answer 1

n(NaOH)=0.4/40===0.01mol

c(OH-)=0.01/0.1==0.1mol/L

C(OH-)*c(H+)=10^-14

c(H+)=10^-13

ph=13

需要盐酸是0.01mol