(4/X+2)+(16X^3/X^4-16)+(8X/X^2+4)+(4/X-2)

1个回答

  • 4/X+2)+(16X^3/X^2-16)+(8X/X^2+4)+(4/X-2) =[4(x-2)+4(x+2)/(x+2)(x-2)+8x/(x^2+4)+16x^3/(x^4-16) =8x/(x^2-4)+8x/(x^2+4)+16x^3/(x^4-16) =8x(x^2+4+x^2-4)/(x^2+4)(x^2-4)+16x^3/(x^4-16) =16x^3/(x^4-16)+16x^3...