Question

浓度为a mol/L 的硫酸钠溶液,如果mg钠离子时,其溶液的体积是 ml ；如果硫酸钠溶液的质量分数为b%,则此硫酸钠

Answer 1

mg Na+物质的量 = m/23 mol

则Na2SO4物质的量 = (m/23)/2 = m/46 mol

溶液体积 = (m/46)/a = m/46 L = 500m/23 ml

如果硫酸钠溶液的质量分数为b%,则此硫酸钠溶液的密度 = (142a/b%)/1000 = 14.2a/b g/ml