Question

若x^2-4分之3-6x+1与2-x分之2x-1的值互为相反数,则x=

Answer 1

若x^2-4分之3-6x+1与2-x分之2x-1的值互为相反数,

则(x^2-4)分之(3-6x)+1+(2-x)分之(2x-1)=0

(3-6x)+x^2-4-(x+2)(2x-1)=0

3-6x+x^2-4-2x^2-3x+2=0

-x^2-9x+1=0

x^2+9-1=0

x=(-9±√85)/2