Question

高次不等式要有详细解释和要有详细计算过程

Answer 1

x^2-x+2 = (x-1/2)^2 + 7/4 >0

(x+2)^4(x-1)^3/[3x+2)^3.(x-2)^2.(x^2-x+2)] >0

(x-1)/(3x+2)>0 (x≠-2,1,-2/3,2)

x> 1 or x< -2/3

ie (x≠-2,1,-2/3,2) and x> 1 or x< -2/3

=> 1