是唯一分拆.
设 A = B1+C1 = B2+C2 ,其中 B1,B2 是对称矩阵,C1,C2 是反对称矩阵
则有 B1-B2 = C2-C1
所以 B1-B2 = B1' - B2' = (B1-B2)' = (C2-C1)' = C2'-C1' = -C2+C1
= -(C2-C1) = - (B1-B2).
所以 B1-B2 = 0
所以 B1 = B2.
进而有 C2-C1 = 0 得 C1=C2.
是唯一分拆.
设 A = B1+C1 = B2+C2 ,其中 B1,B2 是对称矩阵,C1,C2 是反对称矩阵
则有 B1-B2 = C2-C1
所以 B1-B2 = B1' - B2' = (B1-B2)' = (C2-C1)' = C2'-C1' = -C2+C1
= -(C2-C1) = - (B1-B2).
所以 B1-B2 = 0
所以 B1 = B2.
进而有 C2-C1 = 0 得 C1=C2.