Question

设1+2+3+…+m=p,计算x(m-1次方)y·x(m-2次方)·y(3次方)·…·xy(m次方)

Answer 1

[x^(m-1)·y^2]·[x^(m-2)·y^3]·…·[xy^m]

=x^[1+2+3+…+(m-1)]y^(2+3+…+m)

=(xy)^(p-1)