若 | x+y-5 | +根号xy-6 =0,则 x²+y² 的值为多少
4个回答
| x+y-5 | +根号xy-6 =0
x+y-5=0
xy-6=0
x+y=5
xy=6
x²+y²
=x²+y²+2xy-2xy
=(x+y)²-2xy
=5*5-2*6
=13
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