Question

一元二次不等式组的解法x(x2+1)>=(x+1)(x2-x+1)1-2x>3(x-9)求整数解

Answer 1

x(x2+1)>=(x+1)(x2-x+1)

x^3+x>=x^3+1

得x>=1

1-2x>3(x-9)

1-2x>3x-27

1+27>2x+3x

5x