∵∠BAC=90°,EF⊥BC,
∴∠BAC=∠BAD=∠CDE=90°,
∵∠ABD=∠C,
∴△ABD ∽ △ACB,△ABD ∽ △EDC(两角对应相等,两三角形相似)
∴∠ADB=∠ABC,
∴△ABD ∽ △EFB,
且△ABD ∽ △AFD
故选B.
∵∠BAC=90°,EF⊥BC,
∴∠BAC=∠BAD=∠CDE=90°,
∵∠ABD=∠C,
∴△ABD ∽ △ACB,△ABD ∽ △EDC(两角对应相等,两三角形相似)
∴∠ADB=∠ABC,
∴△ABD ∽ △EFB,
且△ABD ∽ △AFD
故选B.