(1)∵灯泡正常发光时的电压为灯泡的额定电压,功率为额定功率
∴灯泡正常发光时的电压为6V,功率为3W,
∵P=UI,
∴通过灯泡的电流I=
P 额
U 额 =
3W
6V =0.5A,
∵I=
U
R ,
∴灯泡的电阻R L=
U 额
I =
6V
0.5A =12Ω;
(2)若将该灯泡接到电压为3V的电源上,
∵灯泡的电阻不变,
∴I′=
U′
R L =
3V
12Ω =0.25A;
此时灯的实际功率:
P 实=U′I′=3V×0.25A=0.75W.
故答案为:5;12;0.5;0.25;0.75.