关于数学极限天才 come here

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m/n-1/(n+1)-1/(n+2)-……-1/(n+m)=[1/n-1/(n+1)]+[1/n-1/(n+2)]+.+[1/n-1/(n+m)]=1/[n(n+1)]+2/[n(n+2)]+...+m/[n(n+m)]所以当n→∞时lim(n^2(m/n-1/(n+1)-1/(n+2)-……-1/(n+m)))=lim{n^2/[n(n+1)]+2n^2/[n(n+2)]+...