(1)
NH3H2O的Kb = 1.76×10^(-5)
2 mol/L 氨水的[OH-] = √(cKb) = √[2*1.76×10^(-5)] = 5.93×10^(-3) mol/L
pH = 14 + lg[OH-] = 11.77
(2)等体积混合后,形成浓度为 1 mol/L 的NH4Cl 溶液
NH4+的Ka = Kw/Kb = 1×10^(-14) ÷ [1.76×10^(-5)] = 5.68×10^(-10)
[H+] = √(cKa) = √[5.68×10^(-10)] = 2.38×10^(-5) mol/L
pH = - lg[H+] = 4.62
(3)没写氨水浓度,无法计算