log5(1/3) x log36 x log6a=2 用换底公式,得 [lg(1/3) /lg5]x[lg6/lg3] x [lga/lg6]=2 lg6约去,[-lg3/lg5]x[lga/lg3]=2 lg3约去,lga/lg5=-2 log5a=-2 a=1/25
log5(1/3) x log36 x log6a=2,求a
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