Question

若b=(sqrt(a^2+1)+sqrt(1-a^2))/(a+1),求a+b的值?

Answer 1

=(sqrt(a^2-1)+sqrt(1-a^2))/(a+1),

sqrt(a^2-1)>=0>a²a≠-1

可得a=1

b=0

a+b=1

题有误:若b=(sqrt(a^2+1)+sqrt(1-a^2))/(a+1),求a+b的值?此题是没法解的

应为:若b=(sqrt(a^2-1)+sqrt(1-a^2))/(a+1),求a+b的值?

题中的(a²+1)应为(a²-1)