h/sinαsinβ*根号下(sin∧α+sin∧β-2sinαsinβcosαcosβ-2sin∧αsin∧β)

1个回答

  • 设α>β>0

    h/sinαsinβ*√(sin^α+sin^β-2sinαsinβcosαcosβ-2sin^αsin^β)

    =h/sinαsinβ*√(sin^α+sin^β-2sinαsinβcosαcosβ-sin^αsin^β-sin^αsin^β)

    =h/sinαsinβ*√(sin^α+sin^β-2sinαsinβcosαcosβ-(1-cos^α)(1-cos^β)-sin^αsin^β)

    =h/sinαsinβ*√[sin^α+sin^β-2sinαsinβcosαcosβ-(1-cos^α-cos^β+cos^αcos^β)-sin^αsin^β]

    =h/sinαsinβ*√[sin^α+sin^β-2sinαsinβcosαcosβ-1+cos^α+cos^β-cos^αcos^β-sin^αsin^β]

    =h/sinαsinβ*√[sin^α+sin^β+cos^α+cos^β-2sinαsinβcosαcosβ-1-cos^αcos^β-sin^αsin^β]

    =h/sinαsinβ*√[1+1-2sinαsinβcosαcosβ-1-cos^αcos^β-sin^αsin^β]

    =h/sinαsinβ*√[1-2sinαsinβcosαcosβ-cos^αcos^β-sin^αsin^β]

    =h/sinαsinβ*√[1-(sin^αsin^β+2sinαsinβcosαcosβ+cos^αcos^β)]

    =h/sinαsinβ*√[1-(sinαsinβ+cosαcosβ)^2]

    =h/sinαsinβ*√[1-(cosαcosβ+sinαsinβ)^2]

    =h/sinαsinβ*√[1-cos^(α-β)]

    =h/sinαsinβ*√[sin^(α-β)]

    =h/sinαsinβ*sin(α-β)

    =h(sinαcosβ-cosαsinβ )/sinαsinβ

    =h(sinαcosβ/sinαsinβ-cosαsinβ/sinαsinβ)

    =h(cosβ/sinβ-cosα/sinα)

    =h(cotβ-cotα)