Question

9a的平方-b的平方+2b-1 分解因式

Answer 1

9a²-b²+2b-1

=9a²-(b²-2b+1)

=9a²-(b-1)²

=(3a+2b-1)(3a-b+1)

(x²-2x)²-1

=(x²-2x+1)(x²-2x-1)

=(x-1)²(x²-2x-1)

2ab-a²-b²+c²

=c²-(a²-2ab+b²)

=c²-(a-b)²

=(c+a-b)(c-a+b)

6a(a+b)(a-b)-3a(a+b)²

=3a(a+b)[2(a-b)-(a+b)]

=3a(a+b)(a-3b)