乙获胜的概率P1 = (1/2)^4 + C4取3 * (1/2)^4 * 1/2 = 3/16
比赛进行完七局的概率P2 = C4取3 * (1/2)^4 = 1/4
记局数为X,则P(X=4)=1/4,P(X=5)=1/4,P(x=6)=1/4,P(x=7)=1/4
乙获胜的概率P1 = (1/2)^4 + C4取3 * (1/2)^4 * 1/2 = 3/16
比赛进行完七局的概率P2 = C4取3 * (1/2)^4 = 1/4
记局数为X,则P(X=4)=1/4,P(X=5)=1/4,P(x=6)=1/4,P(x=7)=1/4